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2 years ago

The circumference of a pizza is 75 inches. What is the approximate radius of the pizza?

Mathematics

2 answers:

zlopas [31]2 years ago

6 0

The approximate radius is 12 inches

AURORKA [14]2 years ago

6 0

C because if you round up 11.94 you get 12. Sorry if it’s wrong it’s been a while since I did this

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ABC is a right triangle with AB = AC. Bisector of ∠A meets BC at D. prove that ∆ ABC ≅ ∆DEF

Olegator [25]

Answer:

Triangles ABC and DEF have the following characteristics :B and E are right angles A=D, BC=EF which congruence theorem can be used to prove ABC =DEF

5 0

2 years ago

4(x−2+y)<br> It's for khan academy

inessss [21]

The answer is 4x-8+4y i think?

4 0

2 years ago

PLSSSSS SOMEONE ANSWER THIS QUESTION

liq [111]

Answer:

12πx⁴, 15x⁷, 16x⁹

Step-by-step explanation:

Volume of a cylinder: πr²h

Volume of a rectangular prism: whl

Plugging in variables for the volume of a cylinder, we get: 3x²·(2x)²·π

3x²·(2x)² = 3·2·2·x·x·x·x

= 12·x⁴

=12x⁴

Now, we just multiply that by π.

12x⁴·π = 12x⁴π

A monomial is a 1-term polynomial, so 12x⁴π is a monomial.

Plugging in variables for the volume of a rectangular prism, we get: 5x³·3x²·x²

5x³·3x² = 5·3·x·x·x·x·x

= 15·x⁵

= 15x⁵

Now, we just multiply that by x².

15x⁵·x²

= 15·x·x·x·x·x·x·x

= 15·x⁷

=15x⁷

A monomial is a 1-term polynomial, so 15x⁷ is a monomial.

Same steps for the last shape, another rectangular prism:

2x²·2x³·4x⁴

2x²·2x³

= 2·2·x·x·x·x·x

= 4·x⁵

= 4x⁵

Now, we just multiply that by 4x⁴.

4x⁵·4x⁴

= 4·4·x·x·x·x·x·x·x·x·x·

= 16·x⁹

= 16x⁹

A monomial is a 1-term polynomial, so 16x⁹ is a monomial.

6 0

1 year ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

3 years ago

Write a simplified polynomial expression in standard form to represent the area of the rectangle below.

Burka [1]

Area of Rectangle = length times width
lets say length = 2x-4
width = x+5

Note: you can switch these around, width could be 2x-4 and length could be x+5, it doesnt matter.

With that being said:
length * width = area
(2x-4)(x+5)=area
FOIL (First Outer Inner Last)
$2x^{2}+10x-4x-20=area$
Simplify:
$x^{2}+6x-20=area$

3 0

2 years ago