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maks197457 [2]
3 years ago
11

3.2.2 7+6 - 9(-2)+(-3)​

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0
Answer in the photo.......
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777÷9=86.3 recurring
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There are 8 triangles in 12 circles what is the simplest ratio triangles to circles
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Answer: 8:12,8to12

Step-by-step explanation:

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What is 4/5+1/3 as a mixed number
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Answer:

1 and 2/15

Step-by-step explanation:

3 0
3 years ago
Select the correct answer. The radius of a nitrogen atom is 5. 6 × 10-11 meters, and the radius of a beryllium atom is 1. 12 × 1
Grace [21]

A negative exponent means the number of the exponent divide by the number. The the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Given information-

The radius of a nitrogen atom is 5.6\times10^{-11} meters.

The radius of a beryllium atom is 1.12 \times10^{-10} meters

<h3>Negative exponents</h3>

A negative exponent means the number of the exponent divide by the number.

As the radius of the nitrogen atom is 5.6\times10^{-11} meters. Convert it in the power of negative exponent of 10.

Let the radius of the nitrogen is r mm. Thus,

r=5.6\times 10^{-11}\\&#10;r=5.6\times 10^{-10-1}\\&#10;r=5.6\times 10^{-10}\times10^{-1}\\&#10;r=\dfrac{5.6\times 10^{-10}}{10} \\&#10;r=0.56\times 10^{-10}

Now the base of the exponents of both the atoms are same. As the radius of the nitrogen atom is 0.56\times 10^{-10} meters and the radius of the beryllium atom is 1.12 \times10^{-10}. Thus the radius of beryllium atom is larger.

To calculate how many times, the radius of beryllium atom should be divided by the radius of a nitrogen atom. Thus,

=\dfrac{1.12\times10^{-10}}{0.56\times10^{-10}} \\&#10;=2

Thus the the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Learn more about the negative exponents here;

https://brainly.in/question/1221452

7 0
3 years ago
Use the quadratic formula to solve x² + 9x + 10 = 0.<br><br> What are the solutions to the equation?
jok3333 [9.3K]

Answer:

-1.30\ and\ -7.70 (2 decimal places)

Step-by-step explanation:

Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

-----------------------------------------------

x^2+9x+10=0

Plug in values:

x=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

First value of x:

x=\frac{-9+\sqrt{41}}{2}=-1.30 (2 decimal places)

Second value of x:

x=\frac{-9-\sqrt{41}}{2}=-7.70 (2 decimal places)

6 0
3 years ago
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