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givi [52]
3 years ago
15

A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.1%, 3.2%

). what is the point estimator of the mean percentage of reservations that are canceled on the day of the flight?
Mathematics
2 answers:
defon3 years ago
6 0
Error = 1/2(Maximum range - Minimum range) = 1/2(3.2-1.1) = % = 0.0105

If p is the point estimator;

Then,
Minimum range = p - Error
Maximum range = p + Error

Solving one of the two expressions,
0.011 = p - 0.0105 => p = 0.011+0.0105 = 0.0215 = 2.15%
alexdok [17]3 years ago
5 0

Answer:



Read more on Brainly.com - brainly.com/question/9975138#read more Error = 1/2(Maximum range - Minimum range) = 1/2(3.2-1.1) = % = 0.0105If p is the point estimator; Then, Minimum range = p - Error Maximum range = p + Error Solving one of the two expressions,0.011 = p - 0.0105 => p = 0.011+0.0105 = 0.0215 = 2.15%

Step-by-step explanation:


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went to dinnerand the bii was 120. left a tip for 21.60 what percent of the total bill did they leave
Irina18 [472]
It is not a tough but a little tricky question. here all the in formations are provided for finding the required answer.The person in the question went to have dinner and his bill was 120. He additionally paid a tips of 21.60. Now the thing that needs to be found is the percentage of tips the person leaves behind.
Let us assume that the percentage of tips left behind = x%
Then we can write the equation as:
120 * (x/100) = 21.60
120x/100 = 21.60
12x/10 = 21.60
12x = 21.60 * 10
12x = 216
x = 216/12
  = 18
So the person left 18% tips.
6 0
4 years ago
I’m having some trouble with this problem if anyone could help out
Murrr4er [49]

Answer: The value is 3

Step-by-step explanation:

6/2=3

18/6=3

54/18=3

162/54=3

Multiply each number by 3

3 0
4 years ago
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mafiozo [28]

Step-by-step explanation:

the answer from the graph is;

(3 , -2)

7 0
3 years ago
A coach’s swimming team practices 5 times per week. There are 4 age groups on the team, and each group practices at a different
oee [108]

Well from what I'm reading it could turn out to be

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4 being the groups and 60 being the minutes they practiced. 5 being the days the coach had to stay and 60 dividing the sum because there is 60 minutes in an hour. So 4×60×5=1200 and 1200÷60=20. So the coach spent 20 hours at practice during the week.

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