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Mariana [72]
3 years ago
10

The Estrada family has established for cable internet service since the pandemic. When establishing the service, there was an in

itial fee as well as a monthly fee on the contract. c(m)=35m+40 represents this scenario. How much has the Estrada family paid for internet service if they began service in March 2020?​
Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

Given:

When establishing the internet service, there was an initial fee as well as a monthly fee on the contract.

The given function is:

c(m)=35m+40

To find:

The cost of internet service if they began service in March 2020.

Solution:

We have,

c(m)=35m+40

We need to find the internet service cost for the first month. So, substitute m=1 in the given function.

c(1)=35(1)+40

c(1)=35+40

c(1)=75

Therefore, the cost of internet service is 75 if they began the service in March 2020.

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Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

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So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

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Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

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Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

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3 years ago
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