Answer:
-6y-y+2=58
-7y+2=58
-7y=58-2
-7y=56
-7y/-7=56/-7
y=-8
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
Bella: 1482
Ricky: 1204
Step-by-step explanation:
Form an equation:
let x be the number of hits ricky has
then bella would have x + 278 hits
So the equation would be:
now, solve
combine like terms
subtract 278 from both sides
divide both sides by 2
since bella has x + 278, she has 1204 + 278 = 1482 hits
Answer:
multiplying by 10^4
Step-by-step explanation:
1,000 = 10^4