Question

A recursive rule for a geometric sequence is

Answer 1

Answer:

C. $a_n=(9)(\frac{2}{3})^{n-1}$

Step-by-step explanation:

Iterative geometric sequence:

$a_n=a_1x^{n-1}$

Recursive geometric sequence:

$a_n=xa_{n-1}$

The equations are very similar and you only really need to rearrange it. The factor (2/3) and the first term (9) are given, so you can write the iterative equation:

$a_n=(9)(\frac{2}{3})^{n-1}$

And so the answer is C.