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Dennis_Churaev [7]
2 years ago
6

Which statements about the graph of y=tax are true

Mathematics
1 answer:
Ket [755]2 years ago
7 0

Answer:

Where are the statments

Step-by-step explanation:

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What is the length of AB?
Xelga [282]

Answer:

<em>AB = 7.35 cm</em>

Step-by-step explanation:

From the attachment,

In ΔDEF,

DF = GH-(GD+FH) = 6 - (2+3) = 1 cm

DE = 2+3 = 5 cm (sum of two radius)

Applying Pythagoras theorem,

EF=\sqrt{DE^2-DF^2}=\sqrt{5^2-1^2}=\sqrt{24}=2\sqrt6

In ΔCDI,

DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm

CD = 2+1.5 = 3.5 cm (sum of two radius)

Applying Pythagoras theorem,

CI=\sqrt{CD^2-DI^2}=\sqrt{3.5^2-2.5^2}=\sqrt6

AB = EF + CI = 2\sqrt6+\sqrt6=3\sqrt6=7.35\ cm

6 0
3 years ago
Read 2 more answers
Which inequality is equivalent to -4g&gt;24
ValentinkaMS [17]

Answer:

look at picture above please

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor
vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

8 0
4 years ago
A cube measures 3.0 CM on each side and has a mass of 25g. What is the density?
Oxana [17]

Answer:

D ≈ 0.925926 g/cm³

Step-by-step explanation:

Density = Mass / Volume

Step 1: Define

M = 25 g

V = (3 cm)³ = 27 cm³

D = ?

Step 2: Substitute and Evaluate for Density

D = 25g / 27 cm³

D = 25/27 g/cm³

D ≈ 0.925926 g/cm³

8 0
3 years ago
The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.
Wittaler [7]

<span>First we calculate z using the formula:

z = (x - μ)/σ</span>

Where:

x = our variable, 10

μ = mean, 8

σ = standard dev, 2

Substituting known values:<span>
z = (10 - 8)/2
z = 2/2
z = 1

Using the tables of the normal distribution to find the p-value with z = 1

p = 0.8413

Since we want "greater than 10”, we need to subtract the probability from 1 therefore

p* = 1 - 0.8413 = <span>0.1587</span></span>

6 0
3 years ago
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