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Fudgin [204]
2 years ago
11

please help will give BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLI

EST BRAINLIEST BRAINLIEST for correct answer!!!!!!!!!!!!!

Mathematics
2 answers:
o-na [289]2 years ago
8 0

Answer:

25 inches is the answer

Temka [501]2 years ago
3 0

Answer:

25 in or 20in

Step-by-step explanation:

it is not  half way if it was it would be  15in its way of half way      

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THANK YOU FOR ANSWERING
anyanavicka [17]

divide the points by the multiplier 1.9

 so 3.8 /1.9 =2

 the base score was 2.0

4 0
2 years ago
What times what eqals 40
uranmaximum [27]
5x8=40 or 40x1=40 this will works
7 0
2 years ago
Read 2 more answers
Whats another way to write 8/5 as a fraction ?
sashaice [31]
16/10

All you have to do to get another way to write a fraction is double the original fraction.

For example...

1/2 = 2/4 = 4/8 = 8/16...
All these are half, 8/16 is the same as 1/2.

Hope this helped. Have a great night!
3 0
3 years ago
Read 2 more answers
I need help plz i give big roux help fast
ArbitrLikvidat [17]

Answer:

Hello, i think that your answer would be c

Step-by-step explanation:

6 0
3 years ago
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

4 0
2 years ago
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