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2 years ago

0.6=x/5 what is the answer please

Mathematics

2 answers:

spin [16.1K]2 years ago

6 0

Step-by-step explanation:

0.6 = x 5 you have to muliply all terms by the same value to elimate fraction denometers

5 0.6 = 5 x5

x = 3

stealth61 [152]2 years ago

3 0

Answer: 3

Step-by-step explanation:

reverse the problem

0.6=x/5

0.6 times 5 = 3

check your work

3/5=0.6

0.6=0.6

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three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

2 years ago

Using the number line above, write the integer that each point represents

zloy xaker [14]

Answer:

E= -6

D= 4

B =- 4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Plz help me I have no idea how to do this

Leviafan [203]

Answer:

0.8

Step-by-step explanation:

cos z = 8/10 = 0.8

8 0

2 years ago

The owner of a grocery store wants to mix two kinds of condy together to make 15lb that he can sell for $5.00 per lb. He wants t

ankoles [38]

Answer: 6 pounds of sugar candy, and 9 pounds of chocolate candy.

Step-by-step explanation:

Let's define the variables:

C = pounds of chocolate candies used.

S = pounds of sugar candies used.

We know that he wants to make a total of 15lb, then:

C + S = 15

We also want that the price per pound to be equal to 5$.

This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.

C*$7.00 + $2.00*S = $5.00*15

Then we have a system of equations:

C + S = 15

C*$7.00 + $2.00*S = $5.00*15

To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:

C = 15 - S

now we can replace that in the other equation:

(15 - S)*$7.00 + $2.00*S = $5.00*15

Now we can solve this for S.

$105 - $5.00*S = $75

$105 - $75 = $5.00*S

$30 = $5.00*S

$30/$5 = S = 6

Then there are 6 pounds of sugar candy, and we can use the equation:

C + S = 15

C + 6 = 15

C = 15 - 6 = 9

There are 9 pounds of chocolate candy in the mix.

3 0

2 years ago

Read 2 more answers

Consider 4 flips of an unfair coin where probability of heads is 0.40. Consider all tosses independent of each other. (a) Compar

romanna [79]

Answer:

a) 0.0256 = 2.56% probability of 4 heads.

0.1296 = 12.96% probability of 4 tails.

b) The probability is 0.0576 = 5.76%.

c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses

Step-by-step explanation:

For each throw, we have these following probabilities:

0.4 = 40% probability of heads.

0.6 = 60% probability of tails.

(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.

4 heads:

4 throws, each with 0.4 probability of heads. So

$(0.4)^4 = 0.0256$

0.0256 = 2.56% probability of 4 heads.

4 tails:

4 throws, each with 0.6 probability of tails. So

$(0.6)^4 = 0.1296$

0.1296 = 12.96% probability of 4 tails.

(b) Determine the probability of H T H T in 4 tosses.

H = 0.4, T = 0.6. So

$p = 0.4*0.6*0.4*0.6 = 0.0576$

The probability is 0.0576 = 5.76%.

(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)

Number of outcomes:

The possible outcomes are:

H - H - T - T

H - T - H - T

H - T - T - H

T - H - H - T

T - H - T - H

T - T - H - H

6 outcomes given 2 heads in 4 tosses.

Each with probability 0.0576, as found in b)

6*0.0576 = 0.3456

0.3456 = 34.56% probability of 2 heads in 4 tosses

8 0

2 years ago