All categories

2 years ago

PLEASE HELP GIVING BRAINLIEST TO THE PERSON WHO ANSWERS CORRECTLY YOU DONT NEED TO DO ALL JUST SOME YOU CAN ANSWER

Mathematics

1 answer:

Rufina [12.5K]2 years ago

6 0

Answers:

1: y = 1x + 0.5

3: the y-intercept shows that the original data began above 0 and has had a steady increase since. (not sure abt this one)

4: I'm sorry i don't know this one

5: the data collection shows that the height to arm span has a ratio of 1 throughout you can tell this by using the line of best fit.

6: according to the line of best fit the height of the person will also be about 66 inches.

7: according to the line of best fit the arm span will also be about 74 inches.

You might be interested in

4. Your class is going to elect a President and Vice President. In how many ways can 2 people be elected if your class has 30 st

lina2011 [118]

Ok so all you have to do is

5 0

2 years ago

Read 2 more answers

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

Jason baked 7 pans of brownies. He gave 1/4 of the brownies to his two sisters. How many pans of brownies did he give to his sis

Marysya12 [62]

Um i think it's 1.75

4 0

3 years ago

Read 2 more answers

Find the Area, I'm pretty sure you suppose to add them all up but my teacher is saying it's wrong

Alexxx [7]

The answer to your question is 6.

5 0

2 years ago

savannah has $5 in her wallet. she owes her brother 20 and owes her sister 18 . she earned 25 babysitting. write an algebraic ex

sladkih [1.3K]

An equation that represents this is

(5-20-18)+25

The steps to solve it are as follows

(-15-18)+25
-33+25= (-8)

she is still 8 dollars in debt

7 0

3 years ago