Answer:
0.4
Step-by-step explanation:
Given:-
- The uniform distribution parameters are as follows:
a = $10,000 b = $15,000
Find:-
Suppose you bid $12,000. What is the probability that your bid will be accepted?
Solution:-
- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].
X ~ U(10,000 , 15,000)
- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:
Pmf = 1 / ( b - a )
Pmf = 1 / ( 15,000 - 10,000 )
Pmf = 1 / ( 5,000 )
Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know
Maximum number of packets = 8
16 ÷ 8 = 2
There are 2 pencils in each packet.
24÷8 = 3
There are 3 erasers in each bag.
Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
What are you solving for?
If you are solving for × then I hope this helps
Let's solve for x.
f(x)= 100−10+e−0.1x
Step 1: Add 0.1x to both sides.
xf+0.1x=−0.1x+e+90+0.1x
xf+0.1x = e+90
Step 2: Factor out variable x.
x(f+0.1) = e+90
Step 3: Divide both sides by f+0.1.
x(f+0.1)/ f+0.1 =e+90/ f+0.1
x=e+90/ f+0.1
Answer:
x= e+90/ f+0.1
