Answer:
We conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
Step-by-step explanation:
Given
Principle P = $2500
Interest rate r = 5% = 0.05
Time period t = 8 years
To determine
Accrue Amount A = ?
Using the compound interest equation
where:
A represents the Accrue Amount
P represents the Principal Amount
r represents the interest rate
t represents the time period in years
n represents the number of compounding periods per unit t
Important tip:
- Given that the interest is compounded 6 times each year, therefore, the value of n = 6.
now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation
∵ 
$
Therefore, we conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
Answer:
the answers to this are x= 1 and y= 9
So volume of a cube=edge legnth cubed so take the cube root of 1000 and get 10
the side legnth is 10 feet
Find the roots
solve
we use hmm, completing the suare
2(x²-1.5x)=4
divide both sides by 2
x²-1.5x=2
take 1/2 of linear coeiftn and square it
-1.5/2=-0.75, (-0.75)²=0.5625
add that to both sides
x²-1.5x+0.5625=2+0.5625
factor perfect squaer trinomial
(x-0.75)²=2.5625
square root both sides, remember to take positive and negative square roots
x-0.75=+/-√2.5625
add 0.75 to both sides
x=0.75+/-√2.5625
the roots are x=0.75+√2.5625 and x=0.75-√2.5625
1/a and 1/b
1/(0.75+√2.5625) and 1/(0.75-√2.5625)
if the roots of a quadratic equation are r1 and r2 then it factors to
(x-r1)(x-r2)
so then we can factor our equation to be
if we were to try and expand it, we would get
x²+0.75x-0.5
that's the simpliest equation with roots 1/a and 1/b where a and b are he roots of 2x²-3x=4
x²+0.75x-0.5 is answer
Answer:
x= -3
y= -2
From the first one, if you add 2y to both sides you can plug that into the second one and solve for y. Then, plug y to the first one and solve for x.
