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OleMash [197]
2 years ago
6

Number 3 on my test

Mathematics
1 answer:
AleksAgata [21]2 years ago
7 0

Answer:

g/e

Step-by-step explanation:

Tan=opp/adj

from the diagram, the opposite is g

the adjacent is e

so Tangent on <G =g/e

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B) A shopkeeper sold her goods for Rs 16,950 allowing 25 % discount and then levied on
Damm [24]

Answer:

Please mark it as the brainliest...

7 0
3 years ago
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that a = 0.95, b = 1.05

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

P(X > x) = 0.9

So

\frac{1.05 - x}{1.05 - 0.95} = 0.9

1.05 - x = 0.9*0.1

x = 1.05 - 0.9*0.1

x = 0.96

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0
3 years ago
Pls helpppp I need the answer asap
zzz [600]

Answer:

CASH = 7284

Step-by-step explanation:

MATHEMATICS = 12345123678

CASH = ?

Find what number the letters represent:

M = 1

A = 2

T = 3

H = 4

E = 5

I = 6

C = 7

S = 8

Then, replace the numbers in the word CASH:

C = 7

A = 2

S = 8

H = 4

Therefore, the number is 7284.

Hope this helps and please mark Brainliest :)

8 0
2 years ago
How many lines are determind by two points
FromTheMoon [43]

Answer:

1 line is determined by 2 points.

Step-by-step explanation:

5 0
3 years ago
Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
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