Question

6x^2 – 13x + 6 = 2x^2 solve using quadratic formula

Answer 1

Answer:

$x=\frac{13\pm\sqrt{73} }{8}$

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS
• Equality Properties

Algebra I

• Standard Form: ax² + bx + c = 0
• Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define equation

6x² - 13x + 6 = 2x²

Step 2: Rewrite in Standard Form

1. Subtract 2x² on both sides:                    4x² - 13x + 6 = 0

Step 3: Define

a = 4

b = -13

c = 6

Step 4: Solve for x/roots

1. Substitute:                              $x=\frac{13\pm\sqrt{(-13)^2-4(4)(6)} }{2(4)}$
2. Exponent:                               $x=\frac{13\pm\sqrt{169-4(4)(6)} }{2(4)}$
3. Multiply:                                  $x=\frac{13\pm\sqrt{169-96} }{8}$
4. Subtract:                                 $x=\frac{13\pm\sqrt{73} }{8}$

And we have our final answer!