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2 years ago

Simplify: 6! - 3!

Mathematics

1 answer:

zheka24 [161]2 years ago

6 0

Could be option A or C

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How many solutions does this equation have?<br> 8−2(n+3)=n+7−3n

svp [43]

8-2(n+3)=n+7-3n

We move all terms to the left:

8-2(n+3)-(n+7-3n)=0

We add all the numbers together, and all the variables

-2(n+3)-(-2n+7)+8=0

We multiply parentheses

-2n-(-2n+7)-6+8=0

We get rid of parentheses

-2n+2n-7-6+8=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

6 0

2 years ago

if I play golf only on Saturday and jog every fourth day. if I play golf and jog on Saturday, how many days will it be before I

shtirl [24]

It will be 28 days when I will jog on Saturday again.

4 0

3 years ago

PLS HELP NEW THIS QUICK!!!

vivado [14]

Answer:

Option C

Step-by-step explanation:

$3\frac{1}{5} \times 2\frac{1}{5}$

Lets convert it into improper fraction.

$\frac{16}{5} \times \frac{11}{5} = \frac{16 \times 11}{5 \times 5} = \frac{176}{25}$

Lets convert $\frac{176}{25}$ into a mixed fraction.

$=> \frac{176}{25} = 7\frac{1}{25} = 7.04$

Rounding off 7.04 gives 7 and rounding 7 further gives 10.

So , the estimate of the product is 10

7 0

2 years ago

Read 2 more answers

How many kilograms a 2 liter jug can hold

vfiekz [6]

2 kg. Each liter is equal to 1 kg

6 0

3 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

5 0

2 years ago