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3 years ago

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. EXRTA POINTS .. DONT SKIP :(( !

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

4 0

Answer:

its D

Step-by-step explanation:

he is incorrect so that leaves us with b or d. and b is wrong about how much cheaper 60% is.

the 40% one is $75.57

the 60% one is $67.98

60% is about 7 dollars less. so it's D

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Show work <br> 3=x+3-5x<br> Please help! Thanks!

alexandr1967 [171]

Answer:x=0

Step-by-step explanation:

subtract 3 from both sides

3=3=x+3-5x-3

simplify

0=x-5x

switch sides

x-5x

add similar elements ; x-5x=-4x

-4x=0

divided both side by -4

-4x/-4 . = . 0/-4

5 0

3 years ago

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Help me please with 2 and 3

IRINA_888 [86]

The answer for #2 is A

And the answer for #3 is B

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3 years ago

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Delaney bought a new car for $34,742 she was surprised that the dealer then added 1,945.55. what was the sales tax rate for this

Gemiola [76]

Answer:

5.6%

Step-by-step explanation:

$34,742. X 5.6% = $1,945.55

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2 years ago

BRAINILIST TO FIRST PERSON TO ANSWER AND GET IT CORRECT!!! please answer fast!

miv72 [106K]

The answer would be 4 divided by 2/3 = 6 tiles

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3 years ago

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Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( !

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. EXRTA POINTS .. DONT SKIP :(( !