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galina1969 [7]
3 years ago
12

Write a letter to a friend in another town invite him or her to spend Christmas holidays with you​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

hey my friend please come over to spend the Christmas holidays with me and my family this year. If you are afraid of your dad it's ok I'll ask my mom to call him and ask him

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Beth bought two pairs of earrings for $12.00 each. She also had to pay 6% sales tax. What was her total bill?
Darya [45]
I’m pretty sure it would be $12.72!
7 0
3 years ago
Read 2 more answers
Complete each ordered pair so that it is a solution of the given linear equation. x - 3y=4;(.-3), (-11, ) The first ordered pair
AURORKA [14]

Answer:

Step-by-step explanation:

x - 3y = 4

x - 3(-3) = 4

x + 9 = 4

x = -5

(-5, -3)

-11 - 3y = 4

    - 3y = 15

        y = -5

(-11, -5)

I don't see how (0, -3) could be a solution to the equation.

3 0
2 years ago
I need to know the step by step on how to solve this question
cluponka [151]
My father taught me a method that I call, 'throwing some thing over the wall'. There is a sample equation for the first picture that shows you how it works. It's a great way to help isolate the variable and I hope that it works for you. The second picture contains the answers I got through the use of this method. I'm sorry for the messy handwriting; I was on a bus.

5 0
3 years ago
I don't get this pls help
dmitriy555 [2]

Answer:

  d, e

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

__

In this case, it means the product is ...

  (6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

__

The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

__

Only the last two choices, d and e, apply.

3 0
3 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
3 years ago
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