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jek_recluse [69]
3 years ago
7

15 fewer than the quantity 222 times c equals c Can you please write this as

Mathematics
2 answers:
vampirchik [111]3 years ago
5 0
As an expression, this is: 
222c - 15 = c
If you want to solve it, add 15 to each side to get: 
222c = c + 15 
Subtract c from each side: 
221c = 15 
Divide each side by 221: 
c ≈ 0.0678733 
Hope this helps!
Lemur [1.5K]3 years ago
3 0
222c -15 = C
Hope this would help
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4 years ago
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Please helppp!! Find the missing side . Round to the nearest tenth
olga nikolaevna [1]

Answer:

7.  7.8

Step-by-step explanation:

We can use Tan of this angle to find the missing side (in this case, the side adjacent to the angle measuring 57°)

 Tan A = (opposite side)/(adjacent side)

    Tan 57° = 12/x

solve for x

           x(Tan 57°) = 12

               x = 12/(Tan 57°)

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6 0
3 years ago
******PLEASE HELP!!******
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Answer:

9^{4}

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7 0
3 years ago
Find dy/dx if y =x^3+5x+2/x²-1
stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

7 0
2 years ago
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