Answer:
Here, BRX and NJY are two triangles in which,
Step-by-step explanation:
 
        
             
        
        
        
<em>☽------------❀-------------☾</em>
<em>Hi there!</em>
<em>~</em>
<em>2.3 to 1 significant figure.</em>
<em>= 2</em>
<em>❀Hope this helped you!❀</em>
<em>☽------------❀-------------☾</em>
<em></em>
 
        
                    
             
        
        
        
The answer is 39 and I know because I took the test and got it right
 
        
             
        
        
        
Answer:
The factorization of  is
 is 
Step-by-step explanation:
This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form  or
 or  . It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
. It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
Let's solve the factorization of  by using the <em>sum and difference of cubes </em>factorization.
 by using the <em>sum and difference of cubes </em>factorization.
1.) We calculate the cubic root of each term in the equation  , and the exponent of the letter x is divided by 3.
, and the exponent of the letter x is divided by 3.
![\sqrt[3]{729x^{15}} =9x^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729x%5E%7B15%7D%7D%20%3D9x%5E%7B5%7D)
 then
 then ![\sqrt[3]{10^{3}} =10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E%7B3%7D%7D%20%3D10)
So, we got that 
 which has the form of
 which has the form of  which means is a <em>sum of cubes.</em>
 which means is a <em>sum of cubes.</em>
<em>Sum of cubes</em>

with  y
 y 
2.) Solving the sum of cubes.


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