12 im guessing if its true like if not delete pz
Answer:
Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean kilograms and standard deviation kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
And the best way to solve this problem is using the normal standard distribution and the z score given by:
We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:
So then the corresponding z scale would be:
Answer:
The working is done in the image attached.
Answer: 20
H(c) = 6.4 + 0.6c
<u>6.4</u> is the constant.
When the height of the cups is <u>18.4</u> the function is:
18.4 = 6.4 + 0.6c
Then, you add <u>6.4</u> from both sides
18.4 - 6.4 + 6.4 = 6.4 + 0.6c - 6.4 + 6.4
Simplify
18.4 = 6.4 + 0.6c
Switch sides
6.4 + 0.6c = 18.4
Multiply both sides by <u>10</u>
6.4 x 10 + 0.6c x 10 = 18.4 x 10
Refine
64 + 6c = 184
Subtract <u>64</u> from both sides
64 + 6c - 64 = 184 - 64
Simplify
6c = 120
Divide both sides by <u>6</u>
6c/6 = 120/6
c = <u>20</u>
<h3>9)</h3><h3>5 planes</h3>
<h3>10)</h3><h3>2 planes</h3>
<h3>11)</h3><h3>BCED</h3>
<h3>12)</h3><h3>Yes , they belong to plane (w)</h3>