Can someone help me w this pls

A company is interested on average wages of employee and variance. A sample of 20 workers is taken and it is found that mean wag

vfiekz [6]

Given that the mean is $9.5 and the standard deviation is $1.30, the standard error will be given by:
σ/√n
where
σ-standard deviation
n=sample size

thus, we shal have:
1.30/√20
=0.2906
Next we find the margin error
0.2906*2=0.581
thus the confidence interval will be:
(9.5+0.581, 9.5-0.581)
=(10.081,8.919)

6 0

3 years ago

You know that the Customer Acquisition Cost is the cost associated with convincing a customer to buy a good or service. It inclu

kozerog [31]

Answer:

The Customer Acquisition Cost for each customer in demographic group 1

The correct option is c

The Customer Acquisition Cost for Group 2

The correct option is b

Step-by-step explanation:

From the question we are told that

The marketing expenses per month for targeting the first group is $E = \$ 30,000$

The marketing expenses per month for targeting the second group is $F = \$ 60,000$

The number of customers for the demography of group 1 that will be attracted is N = 1000

The number of customers for the demography of group 2 that will be attracted is M = 1500

Generally the customer acquisition cost for group 1 is

$K = \frac{E}{ N}$

=> $K = \frac{30000}{ 1000}$

=> $K = \$ 30$

Generally the customer acquisition cost for group 2 is

$Z = \frac{F}{ M}$

=> $Z = \frac{60000}{ 1500}$

=> $Z = \$ 40$

8 0

3 years ago

Angle W and angle X are congruent. If their sum is 121 degrees, what is the measure of angle X?

Nimfa-mama [501]

< W and < X are congruent....so they are equal.....so if their sum is 121....just divide by 2 for ur answer

121/2 = 60.5.....so < W = 60.5 and < X = 60.5

5 0

3 years ago

Andrew ran 20 miles last week (at the same pace) and spent a total of 150 minutes running. If he runs for 240 minutes this week,

swat32

Andrew will run 32 miles.

Explanation:
If you divide the time Andrew ran by the miles he ran, you’ll get 7.5 minutes per mile. Then, if you divide 240 minutes by 7.5, you get 32 miles.

5 0

3 years ago

Read 2 more answers

A data includes 108 body temperature od healthy adult humans having a mean of 98.2 f and a standard deviation of .64f. Contruct

leonid [27]

Answer: ( 98.04f, 98.40f ), it is not accepted

Step-by-step explanation: the question is suggesting we construct a 99% confidence interval for mean body temperature.

The formulae for Constructing a 99% confidence interval is given below as

u = x + Zα/2 × (s/√n)........... For the upper limit

u = x - Zα/2 × (s/√n)........... For the lower limit

Where u = population mean

x = sample mean = 98.2

s = sample standard deviation = 0.64

n = sample size = 108.

Zα/2 = critical value for a 2 tailed test performed at a 1% level of significance ( 100% - 99%) = 2.58

We are making use of our z test because sample size is greater than 30 ( n = 108).

By substituting the parameters, we have that

For upper limit

u = x + Zα/2 × (s/√n)

u = 98.2 + 2.58 ( 0.64/√108)

u = 98.2 + 2.58 ( 0.0616)

u = 98.2 + 0.1589

u = 98.4

For lower limit

u = x - Zα/2 × (s/√n)

u = 98.2 - 2.58 ( 0.64/√108)

u = 98.2 - 2.58 ( 0.0616)

u = 98.2 - 0.1589

u = 98.04.

Hence the 99% confidence interval for mean temperature of human is ( 98.04f, 98.40f )

Using 98.6f as the average mean body temperature is wrong because it is out of the confidence interval calculated above.

Our confidence interval states that at 99% confidence interval, an average human temperature should be at least 98.04f and at most 98.40f.

98.6f is out of the range.

4 0

3 years ago