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3 years ago

what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively

Mathematics

1 answer:

AnnZ [28]3 years ago

7 0

Answer:

$1002$

Step-by-step explanation:

First find difference between the divisors and remainders.

$16-10=6\\18-12=6\\21-15=6$

Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of $(16,18,21)-6$

$16=2^4\\18=2(3^2)\\21=3(7)$

LCM of $(16,18,21)=2^4(3^2)(7)=1008$

Required Number $=1008-6=1002$

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3 years ago

Is 33,44,55 a right triangle?

Paul [167]

Answer:

Yes!

Step-by-step explanation:

We know that right triangles follow the Pythagorean Theorem, where

$a^{2} + b^{2} = c^{2}$

So we will put our side lengths into this formula, keeping in mind that c = the hypotenuse, which is the longest side. a and b are fairly arbitrary.

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3 years ago

Read 2 more answers

Please help asap !!!!!! what vaule of x makes the equation true 3(x-4)=15

DaniilM [7]

3(x-4) = 15

Distribute the 3:

3x-12 = 15

Add 12 to both sides:

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Divide both sides by 3:

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The answer is D. 9

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3 years ago

What are the restrictions of the domain of the function F(x) = 1/x^2-9

Sonbull [250]

$f(x)=\frac{1}{x^2-9}$

The denominator can't be equal to 0.
$x^2-9 \not= 0 \\
x^2 \not= 9 \\
x \not= -3 \ \land \ x \not= 3$

The domain is all numbers except -3 and 3.
$x \in \mathbb{R} - \{-3, 3 \}$

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3 years ago