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schepotkina [342]
2 years ago
7

what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively

Mathematics
1 answer:
AnnZ [28]2 years ago
7 0

Answer:

1002

Step-by-step explanation:

First find difference between the divisors and remainders.

16-10=6\\18-12=6\\21-15=6

Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of (16,18,21)-6

16=2^4\\18=2(3^2)\\21=3(7)

LCM of (16,18,21)=2^4(3^2)(7)=1008

Required Number =1008-6=1002

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X = A 21.6 B 12.9 C 9.1
Artist 52 [7]

Answer:

B: 12.9

Step-by-step explanation:

If A B and C are the alternatives, the answer is B: 12.9

The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.

And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6

Any questions, comment.

6 0
2 years ago
Read 2 more answers
I need help with question 2 Only
kiruha [24]
The correct answer is C
5 0
2 years ago
I need help with this question
Finger [1]
I can’t see it that well sorry
8 0
3 years ago
Page 1
Nadya [2.5K]

Answer:

eweweweweweewwe

Step-by-step explanation:

4 0
3 years ago
4[(10-4) 2 to the second power divided by 4]
SashulF [63]
<span>4[(10-4) 2 to the second power divided by 4]
=4x6x2</span> to the second power divided by 4
=6x2 to the second power 
=6x4
=24
Hope that helps and hope that I didn't misunderstand your question
4 0
3 years ago
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