what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively
1 answer:
Answer:

Step-by-step explanation:
First find difference between the divisors and remainders.

Here, the difference between the divisors and remainders is equal.
So, the required number is equal to LCM of 

LCM of 
Required Number 
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It is 1 16/25
Hope it helps ;-)
Answer:
![\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5By%7C-2%20%E2%89%A4%20y%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%20%E2%88%9E%29%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C-4%20%E2%89%A4%20x%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-4%2C%20%E2%88%9E%29)
Explanation:
<em>See above graph</em>
I am joyous to assist you anytime.
(-2, 2) (8,2) (8, -2) (-2, -2)
Step-by-step explanation:
6x^3 + 47x^2 + 99x + 28
hope it helps you