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schepotkina [342]
3 years ago
7

what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0

Answer:

1002

Step-by-step explanation:

First find difference between the divisors and remainders.

16-10=6\\18-12=6\\21-15=6

Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of (16,18,21)-6

16=2^4\\18=2(3^2)\\21=3(7)

LCM of (16,18,21)=2^4(3^2)(7)=1008

Required Number =1008-6=1002

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3 years ago
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Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

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dividing by 2 on both sides, we will get,

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3 years ago
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Answer:

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