Answer:
Draw an open circle on 2 and continue the arrow left.
Step-by-step explanation:
<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION:
</u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y =
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.
Answer: 24
Step-by-step explanation:
Let the number of defeats be represented by x.
Since the total number of victories exceeds the number of defeats by 4, then the number of victories will be:
= x + 4
We then add the number of victories and losses together and equate them to 44. This will be:
x + x + 4 = 44
2x + 4 = 44
2x = 44 - 4
2x = 40
x = 40/2
x = 20
Therefore number of victories will be:
= x + 4
= 20 + 4
= 24
Answer:
I think it is 192
Step-by-step explanation:
Volume of cube: 5 x 4 x 8 = 160
Area of diagonal: 160/2 = 80
Length of diagonal: 80 / 0.5 x 3 = 480
AB = 480 / 5 x 2 = 192
You could make it true by making it (8x10) plus (8x1)
Explanation: 8x11=88 and 8x10=80 and 8x1=8 and 80+8=88