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3 years ago

Let f(x) = x2 - 1 and g(x) = 2x - 3. Find the new function and write it in simplest form

Mathematics

1 answer:

yawa3891 [41]3 years ago

3 0

Answer:

Option C is the correct answer

${x}^{2} + 2x - 4$

Step-by-step explanation:

$f(x) = {x}^{2} - 1 \\ g(x) = 2x - 3 \\ (f + g)(x) = f(x) + g(x) \\ (f + g)(x) = {x}^{2} - 1 + 2x - 3 \\ \purple{ \boxed{ \bold{ (f + g)(x) = {x}^{2} + 2x - 4}}}$

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How do i know when a set of ordered pairs that represents a function?

pav-90 [236]

Answer:

How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!

Step-by-step explanation:

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3 years ago

There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

Helga [31]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$

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2 years ago

A parking lot has two entrances. Cars arrive at Entrance 1 according to a Poisson Probability Distribution at an average of thre

dusya [7]

Answer:

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3 years ago

When x = 4, the value of 2x0 + x! is

Romashka [77]

4!= 4*3*2*1

Therefore,

2x0+x!= 0+x! = 0+4!

4*3*2*1 = 24 (#1)

4 0

3 years ago

Read 2 more answers

the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

Answer:

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ .

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by $b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21$ {Since $e = \frac{5}{2}$ given}

Therefore, the equation of the given hyperbola will be

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ . (Answer)

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3 years ago