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3 years ago

15

How do i solve this

{6} " align="absmiddle" class="latex-formula">

1 answer:

Elodia [21]3 years ago

6 0

Answer:

You did give anything to solve

Step-by-step explanation:

x⁶ is just a single term

If you had posted an equation like

x⁶ = 64

Take the cube root of both side

x² = 4

Take the square root of both sides

x = ± 2

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Please explain how to get the answer, with step by step explination. I would like to know, so I can do it by my self in the futu

natulia [17]

Answer:

(-8, 135°)

Step-by-step explanation:

(8, -45°) has magnitude 8 and direction -45°.

If we add 180° to the direction and change the sign of the magnitude, we'll have the same point.

(-8, -45° + 180°) = (-8, 135°)

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3 years ago

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4 years ago

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3 years ago

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Lynna [10]

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4 years ago

Read 2 more answers

Let f(x) = 5x3 + 3x2 – 3 and g(x) = x2 + X - 5, fin<br> 4) f(x) + g(x)

aleksley [76]

Answer:

$f(x)+g(x)=5x^{3} +4x^{2}+x-8$

Step-by-step explanation:

Given:

Two functions are given:

$f(x)=5x^{3} +3x^{2} -3$

$g(x)=x^{2} +x-5$

Find $f(x)+g(x)$

Solution:

$f(x)+g(x)=(5x^{3} +3x^{2} -3)+(x^{2} +x-5)$

$f(x)+g(x)=5x^{3} +3x^{2} -3+x^{2} +x-5$

$f(x)+g(x)=5x^{3} +(3x^{2} +x^{2})+x-3-5$

$f(x)+g(x)=5x^{3} +4x^{2}+x-8$

Therefore, the function of $f(x)+g(x)=5x^{3} +4x^{2}+x-8$

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3 years ago