Answer:
Soup A
(need to add more characters to post so)
Answer:
Step-by-step explanation:
(5^3/2)^-2/3 = 0.2 ⇒ E
(256^0.5)^1.25 = 32 ⇒ C
(81^1/6)^3/2 = 3 ⇒ F
(1024^0.03)^20 = 64 ⇒ D
(1000^4/7)^7/3 = 10,000 ⇒ B
(49^5/2)^0.2 = 7 ⇒ A
Step-by-step explanation:
* Lets explain how to solve the problem
- If we have base x to a power n and all to the power of m then we
multiply the two powers to be one power on the base
- [(x^n)^m] = x^(nm)
* Lets solve the problem
∵
∴ (5^3/2)^-2/3 = 0.2 ⇒ E
∵
∵ 256 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2^8
∴
∴ (256^0.5)^1.25 = 32 ⇒ C
∵
∵ 81 = 3 × 3 × 3 × 3 = 3^4
∴
∴ (81^1/6)^3/2 = 3 ⇒ F (answer F must be 3 not 0.333)
∵
∵ 1024 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2^10
∴
∴ (1024^0.03)^20 = 64 ⇒ D
∵
∵ 1000 = 10 × 10 × 10 = 10³
∴
∴ (1000^4/7)^7/3 = 10,000 ⇒ B
∵
∴ (49^5/2)^0.2 = 7 ⇒ A
It would be C!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
Here you go mate
Step 1
n' + 5n™ + 5n 2 equation
Step 2
n' + 5n™ + 5n 2 substitute n=-3
-3+(5)(-3)5(-3)2
step 3
-3+(5)(-3)5(-3)2 add and multiply
answer
27
