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alexandr1967 [171]
3 years ago
7

P=21+2w; if p=18 when l=5, find w

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0

Answer:

if im not mistaken.. i would say its -3.5 or -7/2

Step-by-step explanation:

Rashid [163]3 years ago
6 0

Answer:

Exact form: w = -3/2

Decimal form: w = -1.5

Mixed number form: w = -1 1/2

Step-by-step explanation:

<em>isolate</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>by</em><em> </em><em>dividing</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>factors</em><em> </em><em>that</em><em> </em><em>don't</em><em> </em><em>contain</em><em> </em><em>the</em><em> </em><em>variable</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em>!</em><em>!</em>

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Dovator [93]
Bear with my working out lol,

8x3 = 24in^2
9x12 = 108in^2
6x7 = 42in^2
(11x4) / 2 = 22in^2

Total = 196in^2

Try that, I couldn’t tell where the tip on the triangle fell at. So it could be wrong but that is what I got and what I would put :)
4 0
3 years ago
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What if it was for 20 months
olya-2409 [2.1K]

Answer:

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608.334 days and 86.9049 months

6 0
3 years ago
What is the gcf of 92 and 100
Elena-2011 [213]
92= \textcircled{2} \times \textcircled{2} \times 23 \\&#10;100=\textcircled{2} \times \textcircled{2} \times 5 \times 5 \\ \\&#10;GCF(92,100)=\textcircled{2} \times \textcircled{2} =4

The GCF of 92 and 100 is 4.
5 0
3 years ago
Given triangle, ABC is congruent to triangle EDC find A
arlik [135]

Answer:

m<A = 30 degrees.

Step-by-step explanation:

m < C in triangle ABC = m < C in EDC so

x + 13 + 42 + x + 13 = 180

2x = 180 - 13 - 13 - 42

2x = 112

x = 56.

So m < C = 56+13 = 69.

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7 0
2 years ago
A/ab-bsquare + b/ab-asquare?​
lord [1]

Answer:

\dfrac{(a+b)}{ab}

Step-by-step explanation:

The given expression is :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}

It can be solved as follows :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

So, the solution of the given expression is equal to \dfrac{(a+b)}{ab}.

7 0
3 years ago
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