Question

Please help. Question listed below

Answer 1

Answer:

$f^{-1}$(x) = ( $\frac{9x-1}{8}$ )²

Step-by-step explanation:

f(x) = $\frac{8\sqrt{x} +1}{9}$

y = $\frac{8\sqrt{x} +1}{9}$

Solve equation for x

8√x + 1 = 9y

8√x = 9y - 1

√x = $\frac{9y-1}{8}$

(√x)² = ( $\frac{9y-1}{8}$ )²

x =  ( $\frac{9y-1}{8}$ )²

Switch "x" and "y"

y = ( $\frac{9x-1}{8}$ )²

$f^{-1}$(x) = ( $\frac{9x-1}{8}$ )²