1) 3
2) 8
3)10
4)-4
Hope this helped
Answer:

Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
The egation is 58/0.79=73
the cocoa ways 73% of the grams and 73% of 58 is 42 so the cocoa weighs 42 grams in total
H^2 + 3.5 = 20^2
That is the formula
Answer:
Original garden: 42 feet
Enlarged garden: 98 feet
Step-by-step explanation:
Perimeter = length (2) + width (2)
<u>Original perimeter:</u>
P = 15(2) + 6(2)
P = 30 + 12
P = 42 feet
In this problem, similar is proportional, so the new garden will be proportional to the old one.
If the original length was 15 and the new length is 35, then 15 would have had to have been multiplied by 2 1/3. That means you need to multiply 6 by 2 1/3, which is 14. That means the dimensions of the enlarged yard is 14 (width) × 35 (length).
<u>Enlarged perimeter</u>
P = 35(2) + 14(2)
P = 70 + 28
P = 98 feet