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3 years ago

X 17- 5 + 17 싸 What is X? ?

Mathematics

1 answer:

aev [14]3 years ago

5 0

You need to rewrite this equation and then i can help

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HELP!! <br> A. 40<br> B. 50<br> C. 90<br> D.180

Dafna11 [192]

Answer:

50 degrees

Step-by-step explanation:

5 0

3 years ago

A line passes through the point (4,-2) and has a slope of 1/2 what is the value of a if the point (-4,a) is also on the line

Slav-nsk [51]

Answer: The value of a is -6.

Step-by-step explanation:

To do this we need to find the y-intercept first.

-2= 4(1/2) + b

-2=2+ b

-2 -2

b= -4 so now the y-intercept is -4 so we will now have the equation y= 1/2x -4

so now put -4 into the equation for x and solve for y.

y= 1/2(-4) -4

y = -6

3 0

3 years ago

I have to be awake at 5am and it’s about to be 12am so can someone please help me with this 7th grade math homework

finlep [7]

Step-by-step explanation:

Divide the denominator by the numerator to find the percentage

5 0

3 years ago

7.) If a circle has a diameter of 40 inches, what is the same circles radius?

My name is Ann [436]

The radius is always half of the diameter so it would be 20 inches

5 0

3 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

5 0

3 years ago