Answer:

Step-by-step explanation:
Given: 
We need to completely isolate
to solve.






Finally, multiply both sides by -2 to completely isolate
.

Answer: (D) <em>bottom right graph</em>
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: f(x) = a(x - h)² + k, where
- (h, k) is the vertex
- |a| is the vertical stretch
- sign of "a" determines the direction of the parabola
Given g(x) = (x - 3)² - 5
- vertex (h, k) = (3, -5)
- vertical stretch |a| = 1
- sign of "a" is positive so parabola points up
The only graph that satisfies all of these conditions is the bottom right.
Answer:
N/A.
Step-by-step explanation:
I will not answer your question and I will be flagging it due to you adding a test/exam question.
Given:
'a' and 'b' are the intercepts made by a straight-line with the co-
ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get



Multiply both sides by a.

The value of a is 2. So, x-intercept is 2.
Putting a=2 in
, we get


The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get

Therefore, the equation of the required line in intercept form is
.