The expression that would be added to both sides is (b/2a)^2
<h3>How to determine the expression?</h3>
The equation is given as:
x^2 + b/ax + __ = c/a + __
Take the coefficient of x
b/a
Divide by 2
b/2a
Square the expression
(b/2a)^2
Hence, the expression that would be added to both sides is (b/2a)^2
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Its algebra. The original equation is

To solve for a variable, we reverse the order of operations, beginning with addition/subtraction, and then multiplication/division. To remove a number from one side, we must do the opposite to the other side. In this case, to get rid of the -121 we must add 121 to the -164. This gives us -43. Then, to get the x by itself, we must multiply the other side by 3. -43*3=129
When we are doing the opposite of an operation to the other side, we are really reversing the operation and, to keep both sides equal, we must do whatever we have done to one side to the other side. So when we have -121, we add 121 as it equals 0, therefore it is gone. Since a equation must be balanced, we have to do what we did to the other side (adding 121).
<span>The answer should be 14t - 2m2 - 5/2 , if I am correct</span>
Answer:
21 3/4
Step-by-step explanation:
3 times 7 1/4 since the scale is 1:7 1/4. Good luck!! :)