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Mekhanik [1.2K]
3 years ago
13

3 divided by 5 (step by step)​

Mathematics
1 answer:
snow_lady [41]3 years ago
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There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model
Helga [31]

\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill

A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}

7 0
2 years ago
Please Help. Thank you
jeyben [28]
The answer is D. A translation does not change a figure's size or shape because each of its points are moved the same amount and in the same direction(s).
8 0
3 years ago
What's the percent of 18?
Harman [31]
18% = 18 / 100 = 0.18;
4 0
3 years ago
Find the area.<br> 8 in<br> 19 in<br> 13 in<br> 1976 in²<br> 205 in²<br> 128 in²<br> 104 in²
sveticcg [70]

Total area = 104+24 = 128 sq.in ,  Option C is the right answer.

The missing figure is attached with the answer.

<h3>What is Area ?</h3>

The space occupied by a two dimensional figure is called Area.

The figure given in the question can be divided into two figure

A rectangle of 8 * 13 inch

and a triangle of 8 * 6 inch

The area of a rectangle is given by

Length * Breadth

8 * 13

= 104 sq.inch

The area of the triangle is given by

(1/2) * base * height

= (1/2) * 8 * 6

= 24 sq.inch

Total area = 104+24 = 128 sq.in

Therefore Option C is the right answer.

To know more about Area

brainly.com/question/27683633

#SPJ1

6 0
2 years ago
Is y=x^3 a solution of the differential equation yy'=x^5+y
shepuryov [24]

No; we have y=x^3\implies y'=3x^2. Substituting these into the DE gives

3x^5=x^5+x^3

which reduces to x^3=0, true only for x=0.

3 0
3 years ago
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