Answer: (-1/2)^3
-0.125
Step-by-step explanation:
The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
C
Step-by-step explanation:
i took test
Answer:
9
Step-by-step explanation:
2/5 x 2 = 4/5
4/5 x 2, or 2/5 x 4 = 1 3/5
1 3/5 x 2, or 2/5 x 8 = 3 1/5
3 1/5 + 2/5, or 2/5 x 9 = 3 3/5
