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Marina86 [1]
3 years ago
15

Can someone please help me on number 16-ABC

Mathematics
1 answer:
melomori [17]3 years ago
7 0

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

<u>Part a) Is x = 0 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

<u>Part b) Is x = 4 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

-2x\:

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)>10\left(-1\right)

Simplify

2x>-10

Divide both sides by 2

\frac{2x}{2}>\frac{-10}{2}

x>-5

-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}

<u>solving -6 < -2x</u>

-6 < -2x

switch sides

-2x>-6

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)

Simplify

2x

Divide both sides by 2

\frac{2x}{2}

x

-6

Thus, the two intervals:

\left(-\infty \:,\:3\right)

\left(-5,\:\infty \:\right)

The intersection of these two intervals would be the solution to both inequalities.

\left(-\infty \:,\:3\right)  and \left(-5,\:\infty \:\right)

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR  -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

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9x-8(x-6)=52 what is the answer
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Answer:

x = 4

Step-by-step explanation:

Step 1: Write equation

9x - 8(x - 6) = 52

Step 2: Solve for <em>x</em>

  1. Distribute -8: 9x - 8x + 48 = 52
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Step 3: Check

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What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°
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Answer:

16.75 square cm

Step-by-step explanation:

Area  \: of  \: sector  =  \frac{ \theta}{360 \degree}  \times \pi {r}^{2}  \\  \\  =  \frac{30 \degree}{360 \degree}  \times 3.14 \times  {8}^{2}  \\  \\  =  \frac{1}{12}  \times 3.14 \times 64 \\  \\  =  \frac{1}{3}  \times 3.14 \times 16 \\  \\  =  \frac{1}{3}  \times 50.24 \\  \\  = 16.7466667 \\  \\Area  \: of  \: sector  = 16.75 \:  {cm}^{2}

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How much difference do a couple of weeks make for birth weight? Late-preterm babies are born with 34 to 36 completed weeks of ge
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Answer:

a) 0.3277

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Step-by-step explanation:

We are given the following information in the question:

N(2750, 560).

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Standard Deviation, σ = 560

We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P (less than 2500 grams)

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P( x < 2500) = P( z < \displaystyle\frac{2500 - 2750}{560}) = P(z < -0.4464)

Calculation the value from standard normal z table, we have,  

P(x < 2500) = P(z < -0.4464) = 0.3277 = 32.77\%

b) P ((less than 1500 grams)

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Calculation the value from standard normal z table, we have,  

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Answer:

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Step-by-step explanation:

If the slope is moving up from left to right, then it is positive

If the slope is moving down from left to right, then it is negative

If the slope is a vertical line and is not moving left/right, then it is undefined

If the slope is a horizontal line and is not moving up/down, then it is zero

So slope 1 would be positive because it is moving up from left to right.

Slope 2 would be negative because it is moving down from left to right.

Slope 3 would be zero because it is a horizontal line that is not moving up or down.

Hope this helped!

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