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3 years ago

What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°

Mathematics

1 answer:

IceJOKER [234]3 years ago

3 0

Answer:

16.75 square cm

Step-by-step explanation:

$Area \: of \: sector = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{30 \degree}{360 \degree} \times 3.14 \times {8}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 64 \\ \\ = \frac{1}{3} \times 3.14 \times 16 \\ \\ = \frac{1}{3} \times 50.24 \\ \\ = 16.7466667 \\ \\Area \: of \: sector = 16.75 \: {cm}^{2}$

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To learn more about Frequency tables, please check: brainly.com/question/27344444

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2 years ago

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3 years ago

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3 years ago

after a picnic 5/12 of the cornbread is leftover. val eats 4/5 of the leftover cornbread what fraction of the cornbread does val

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5/12 - 4/5 = -23/60. You can't simplify -23/60. Hope this is right

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3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

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$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .

After you succesfully solve it, you should get the answer $x=20$ .

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4 years ago