Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer with Step-by-step explanation:
The radius of the bull’s-eye of the dartboard is 8 inches.
The radius of each concentric circle is 8 inches more than the radius of the circle inside it.
Radius of first circle=8 in.
Radius of second circle=16 in.
Radius of third circle=24 in.
Radius of fourth circle=32 in.
Area of C=Area of the third circle-Area of second circle
= π×24×24-π×16×16
= 320π sq. in.
Total area of dartboard=Area of fourth circle=π×32×32
=1024π sq. in.
P( the dart will hit in area C)= area of c/total area of dart board
=320π/1024π
= 5/16
Hence, correct option is:
B.5/16
Answer:
It's where point B is at (2,0.5)
The answer is D they are proportional equal to negative 4<span />
A) 21 (21 - 1 = 20)
B) 75 (8 x 15 = 120; 120 - 3 - 10 - 8 - 3 - 10 - 1 - 10 = 75)
C) 6 (any value close to the mean)
