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morpeh [17]
3 years ago
13

Solve for a and b. please help.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

a= 22.5

b= 37.5

Step-by-step explanation:

<u>In</u><u> </u><u>△</u><u>BCD</u><u>:</u>

Applying Pythagoras' Theorem,

a² +30²= b²

a² +900= b² -----(1)

<u>In</u><u> </u><u>△</u><u>ABC</u><u>:</u>

Applying Pythagoras' Theorem,

b² +50²= (40 +a)² -----(2)

Substitute (1) into (2):

a² +900 +50²= 40² +2(40)(a) +a²<em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>expand</em><em> </em><em>bracket</em><em>)</em>

a² +900 +2500= 1600 +80a +a²

a² +3400= a² +80a +1600 <em>(</em><em>simplify</em><em>)</em>

a² +3400 -a² -80a -1600= 0 <em>(</em><em>bring</em><em> </em><em>everything</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>)</em>

-80a +1800= 0

80a= 1800 <em>(</em><em>+</em><em>8</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

a= 1800 ÷80

a= 22.5

Subst. a= 22.5 into (1):

22.5² +900= b²

b²= 506.25 +900

b²= 1406.25

b= √1406.25 <em>(</em><em>square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 37.5 <em>(</em><em>reject</em><em> </em><em>negative</em><em> </em><em>value</em><em> </em><em>since</em><em> </em><em>b</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>length</em><em>)</em>

☆(a +b)²= a² +2ab +b²

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