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kupik [55]
3 years ago
5

Name 2 decimals whose difference is 0.4

Mathematics
2 answers:
marta [7]3 years ago
6 0

Answer:

0.1 and 0.5

Step-by-step explanation:

11111nata11111 [884]3 years ago
4 0

Answer:

.8-.4=.4 and .12-.8=.4

Step-by-step explanation:

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HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!
kiruha [24]

Answer:

b

i did this before xD

6 0
3 years ago
Graph the quadratic variation if g(x) varies directly with x^2, and g(x) = 75 when x = 5.
Darina [25.2K]

Answer:

Third graph from the top

Step-by-step explanation:

Formula for g(x) is  g(x) = 3 · x∧2

When we replace x=5 in the formula we get:

g(5) = 3 · 5∧2 = 3 · 25 = 75

God with you!!!

5 0
3 years ago
Find the difference quotient and simplify your answer. f(x) = 4x − x2, f(4 + h) − f(4) h , h ≠ 0
Anon25 [30]

The difference quotient and simplification will be    = [4 -h-2x]

The given equation is as follows:   f(x)= 4x - x²

For finding the quotient and further simplification we must follow the following steps:

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

<h3>What is simplification of algebraic operations?</h3>

Getting the functions in their lowest terms is known as simplification.

Brackets will get open and solved further;

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

[f(x + h) - f(x)] / h = [4h - h² - 2x]/ h  

Finally dividing the whole equation with h;

                                = [4 - h - 2x] 

Learn more about algebraic operations,

brainly.com/question/12485460

# SPJ1

7 0
1 year ago
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Given f(x) = 2x – 3, find the x value such that f(x) = 8.
jok3333 [9.3K]

Answer: 5.5

Step-by-step explanation:

Plugging it into the formula, we get

2x-3 = 8

Add 3 to both sides:

2x = 11

Divide by 2 on both sides:

x = 5.5

4 0
3 years ago
Read 2 more answers
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