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2 years ago

Which of the following has a unit rate of $13.50 per shirt?

Mathematics

2 answers:

Nitella [24]2 years ago

7 0

Answer:

B. 6 shirts for $81

Step-by-step explanation:

When calculating the unit rate in scenarios like this, you have to divide the money by the product. That is because you are splitting the money, not the product itself. You can easily eliminate C and D by knowing the 12x12 multiplication table. A is not the answer because 53/4 = 13.25. The only answer left is B, and 81/6 = 13.50

Helen [10]2 years ago

4 0

Answer:

B 6 shirts for 81

Step-by-step explanation:

81/6 = 13.5

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At a NASCAR racetrack, the distance per lap is 2 miles. Lou Lambert drives his car at a constant rate of 160 miles per hour. Ral

Nezavi [6.7K]

Answer:

24 minutes

Step-by-step explanation:

Given:

Distance per lap = 2 miles

Speed of Lou Lambert = 160 miles/hr

Speed of Ralph Redding = 170 miles/hr

Speed difference between the two = 170 - 160 = 10 miles/hr

Therefore, we can say that Ralph gains 10 miles in 60 minutes over Lou.

We have to find the time in which Ralph will gain 2 laps i.e. 2 $\times$ 2 = 4 miles.

Let us use unitary method to find the required time.

10 miles are gained by Ralph in 60 minutes

1 mile will be gained in $\frac{60}{10} = 6\ minutes$

4 miles will be gained in 6 $\times$ 4 = 24 minutes

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3 years ago

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True [87]

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3 years ago

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Serjik [45]

Answer:

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Step-by-step explanation:

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2 years ago

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Si el área de una figura rectangular esta dada por A-bxh,¿cual es la siguiente expresiones representa el área de la puerta

stealth61 [152]

Respuesta:

3x² + 5x - 2

Explicación paso a paso:

Dado que :

Área del rectángulo, A = largo * ancho

Dimensión = 3x - 1; x + 2

Área = (3x - 1) * (x + 2)

Área = 3x² + 6x - x - 2

Área = 3x² + 5x - 2

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2 years ago

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$