What problem is there to show work for?
Answer:
p = -6
Step-by-step explanation:
1) Distribute 3 through the parenthesis {3p + 12 = p}
2) Subtract 12 from each side {3p = p - 12}
3) Subtract p from each side {2p = -12}
4) Divide each side by 2 {p = -6}
All you need to do is put 45 over 100 to make it 45/100, then simplify down until you get your answer. The answer is 9/20 though. There may be better ways, but that's how I do it.
There are 8 proper fractions with a denominator of 30 that are irreducible:
1/30, 7/30, 11/30, 13/30, 17/30, 19/30, 23/30, 29/30
We cannot count any even numerators, as 30 is even and would therefore make the fraction reducible.
We cannot count any numerators that are a multiple of 3, as it is a factor of 30. Likewise we cannot count any numerators that are a multiple of 5.
Here is the answer and the explanation.
