Can’t help you with this, we need either the picture of the graph or the formula for the graph
This is the case of Inductive Arguments. In logic, inductive arguments are all about the content of the premises and involve probability. Logicians focus on the strength of this type of argument. In a strong inductive argument, if the premises are assumed true, it is likely<span> that the conclusion is true, it does not mean that it must be true, it is possible that the conclusion could be false. Thus, if the conclusion is likely to not be true based on the assumed truth of the premises, the inductive argument is weak.
</span><span>While there are mathematical ways to determine probability, most of the time you'll have to use your intuition and experience to help you figure out whether an inductive argument is strong or weak.</span>
So according to this, given that Ryan is conducting an observational study on human behavior in different environments. To get the most accurate conclusion he needs to get the <span>greatest sample size, that is 50 Individuals. </span>
<span>In
the given situation, a jewelry maker has the following:
=> 24 jade beads
=> 30 teak beads
Now, how many necklace can a jewelry maker make with this number of beads.
=> 24 + 30 = 54
=> (8 x 3) + (10 x 3) = 54
=> (8 + 10) x 3 = 54
=> 18 x 3 = 54
=> 54 = 54
Thus, the number of necklace is 3 with 8 jade and 10 teak beads in it.
</span>
Answer:
Infinite number
Step-by-step explanation:
we know that
If one angle is 90°, and another half of that, then it must be 45° and so the third angle is also 45°. (The sum of the internal angles of a triangle must be equal to 180 degrees)
Remember that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
therefore
There is an infinite number of unique triangle with these angles.
Answer:
Dexter is weird :[
Step-by-step explanation:
For one to make a scale model of his room they must be ill in the mind (cray-cray) or bored (lonely)
I hope this helped ;))
