Help please!!!!!!!!!

Mathematics

1 answer:

fomenos3 years ago

7 0

Step-by-step explanation:

by Pythagoras theorem :

base ²+ perpendicular ² = hypotenuse ²

base = 5cm

perpendicular = 8 cm

hypotenuse = h cm

5²+ 12² = h²

25 + 144 = h²

169 = h²

h = √ 169 = 13 cm

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you .

You might be interested in

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o

Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

$\mu -2\sigma = 55 -2*6 =43$

$\mu +2\sigma = 55 +2*6 =67$

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

$100 -0.15-2.5 = 97.85$

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

$\mu = 55, \sigma =6$

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

$\mu -2\sigma = 55 -2*6 =43$

$\mu +2\sigma = 55 +2*6 =67$

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

$100 -0.15-2.5 = 97.85$

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%