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2 years ago

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Polygon ABCDE is reflected across the x-axis to form polygon A′B′C′D′E′. Then polygon A′B′C′D′E′ is dilated by a scale factor of

0.5 about D′ to form polygon LMNOP. Vertices A and B correspond to L and M, respectively.

1 answer:

PIT_PIT [208]2 years ago

6 0

Hope this helps
The vertices<span> of </span>polygon ABCD<span> are at A(1, 1), </span>B<span>(2, 3), </span>C<span>(3, 2), and </span>D<span>(2, 1). </span>ABCD<span> is </span>reflected across<span> the </span>x-axis<span> and translated 2 units up to </span>form polygon<span> - 914438.</span>

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2 years ago

Write 14/25 29/50 53/100 13/20 and 3/5 in order from greatest to least

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13/20,3/5,29/50,14/25,53/100

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Peter is packing toys into boxes each box holds 30 toys they are 94 toys and 3 boxes how many toys are there left

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1 year ago

Read 2 more answers

Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12 8x -3y &g

liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

$10x + 4y < 12$

$8x - 3y > 20$

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

$10x + 4y < 12$

$10 * 3 + 4 * -8 < 12$

$30 - 32 < 12$

$-2 < 12$ --- True

$8x - 3y > 20$

$8 * 3 - 3 * -8> 20$

$24 +24> 20$

$48> 20$ --- True

(2, 5)

x = 2 and y = 5

$10x + 4y < 12$

$10 * 2 + 4 * 5 < 12$

$20 + 20 < 12$

$40 < 12$ --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

$10x + 4y < 12$

$10 * -5 + 4 * 1 < 12$

$-46 < 12$ --- True

$8x - 3y > 20$

$8 * -5 - 3 * 1 > 20$

$-43 > 20$ --- False

(10, 3)

x = 10 and y = 3

$10x + 4y < 12$

$10 * 10 + 4 * 3 < 12$

$112 < 12$ --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

$10x + 4y < 12$

$10 * 2 + 4 * -10 < 12$

$-20 < 12$ --- True

$8x - 3y > 20$

$8 * 2 - 3 * -10 > 20$

$46 > 20$ --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

4 0

2 years ago

(-6,8); perpendicular to y = -3/2x -1

UNO [17]

Answer:

$y = \frac{2}{3} x + 12$

Step-by-step explanation:

$y = - \frac{3}{2} x - 1$

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line= $- \frac{3}{2}$ .

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

$- 1 \div ( - \frac{3}{2} ) \\ = - 1( - \frac{2}{3} ) \\ = \frac{2}{3}$

Substitute m= $\frac{2}{3}$ into y=mx+c:

$y = \frac{2}{3} x + c$

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

$8 = \frac{2}{3} ( - 6) + c \\ \\ 8 = - 4 + c \\ c = 8 + 4 \\ c = 12$

Thus, the equation of the line is $y = \frac{2}{3} x + 12$ .

7 0

2 years ago