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Marizza181 [45]
3 years ago
9

14)

Mathematics
1 answer:
poizon [28]3 years ago
4 0

Answer:

f(x) = 2x+5

Step-by-step explanation:

Given the arithmetic sequence shown

7,9, 11, 13, 15, 17,

THe nth term of the sequence is expressed as;

Tn = a + (n-1)d

a is the first term = 7

d is the common difference = 9-7 = 11-9 = 2

Substitute

Tn = 7 + (n -1)*2

Tn = 7 + 2n - 2

Tn = 2n + 5

Hence the required function is f(x) = 2x+5

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You measure the weight of 38 bags of nuts, and find they have a mean weight of 78 ounces. Assume the population standard deviati
Ket [755]

Answer: The maximal margin of error is 4.822.

Step-by-step explanation:

Since we have given that

Number of bags = 38

Sample mean = 78 ounces

Standard deviation = 14.5 ounces

At 96% confidence interval for the true population mean bags of nut weight.

So, z = 2.05

As we know that formula for "Margin of error":

z\times \dfrac{\sigma}{\sqrt{n}}\\\\=2.05\times \dfrac{14.5}{\sqrt{38}}\\\\=4.822

Hence, the maximal margin of error is 4.822.

8 0
4 years ago
(c^3b^1a^4)^4 + 3a^16b^4c^12
azamat

Answer: 4a16b4c12

Step-by-step explanation:

5 0
3 years ago
Helppppppp pleaseeee​
Alenkinab [10]

Answer:

A

Step-by-step explanation:

2.5 x 3.4 = 8.5

5 0
3 years ago
Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.
boyakko [2]

Answer:

Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.  

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.

3 0
3 years ago
Read 2 more answers
Lim x--> 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

\dfrac{e^x}{\cos x} is continuous at x=0, and \dfrac{e^0}{\cos 0}=1. The remaining limit is also 1, since

\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
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