All categories

3 years ago

14)

Mathematics

1 answer:

poizon [28]3 years ago

4 0

Answer:

f(x) = 2x+5

Step-by-step explanation:

Given the arithmetic sequence shown

7,9, 11, 13, 15, 17,

THe nth term of the sequence is expressed as;

Tn = a + (n-1)d

a is the first term = 7

d is the common difference = 9-7 = 11-9 = 2

Substitute

Tn = 7 + (n -1)*2

Tn = 7 + 2n - 2

Tn = 2n + 5

Hence the required function is f(x) = 2x+5

You might be interested in

You measure the weight of 38 bags of nuts, and find they have a mean weight of 78 ounces. Assume the population standard deviati

Ket [755]

Answer: The maximal margin of error is 4.822.

Step-by-step explanation:

Since we have given that

Number of bags = 38

Sample mean = 78 ounces

Standard deviation = 14.5 ounces

At 96% confidence interval for the true population mean bags of nut weight.

So, z = 2.05

As we know that formula for "Margin of error":

$z\times \dfrac{\sigma}{\sqrt{n}}\\\\=2.05\times \dfrac{14.5}{\sqrt{38}}\\\\=4.822$

Hence, the maximal margin of error is 4.822.

8 0

4 years ago

(c^3b^1a^4)^4 + 3a^16b^4c^12

azamat

Answer: 4a16b4c12

Step-by-step explanation:

5 0

3 years ago

Helppppppp pleaseeee

Alenkinab [10]

Answer:

Step-by-step explanation:

2.5 x 3.4 = 8.5

5 0

3 years ago

Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.

boyakko [2]

Answer:

Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.

which can be factored as follows:

3 0

3 years ago

Read 2 more answers

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago