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olga_2 [115]
2 years ago
14

a group of students went hiking in wildlife sanctuary. during the hike a total of 180 ticks and mosquitoes were slapped. if thes

e pests had a total of 1240 legs, how many mosquitoes and how many ticks were slapped during the hike?(hint: ticks have 8 legs and mosquitoes have 6 legs)
Mathematics
1 answer:
SVEN [57.7K]2 years ago
3 0

Answer:

m = 100, t = 80

Step-by-step explanation:

m +  t = 180

6m + 8t = 1240

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2 i hope this helps ok bye
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Which equation is correct
Sergeeva-Olga [200]
1. Two of the main identities used in trigonometry for right triangles (Triangles that have an angle of 90°) are: Sine (Sin) and Cosine (Cos).


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7 0
3 years ago
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The Sahara Desert has an area of approximately 9,400,400 km2. While estimates of its average depth vary, they center around 150
horrorfan [7]

It would take 65433661 years to re-create the Sahara Desert

<h3>How many years would it take to re-create the Sahara Desert?</h3>

The given parameters are:

Surface area = 9,400,400 km^2

Depth = 150 m

This means that the volume is

Volume = Surface area * Depth

So, we have

Volume = 9,400,400 km^2 * 150 m

Express as meter square

Volume = 9,400,400 * 1000000 m^2 * 150 m

Evaluate the product

Volume = 9,400,400 * 150,000,000 m^3

A small dump holds 20.5 m^3 for 30 seconds.

So, the duration is:

Time = (9,400,400 * 150,000,000 m^3)/(20.5 m^3 per 30 seconds)

Evaluate the product and quotient

Time =  2.0635024e+15 seconds

1 second = 3.171e-8 year.

So, we have:

Time =  2.0635024e+15 * 3.171e-8 year

Evaluate the product

Time = 65433661.104 years

Approximate

Time = 65433661 years

Hence, it would take 65433661 years to re-create the Sahara Desert

Read more about rates at:

brainly.com/question/19493296

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4 0
2 years ago
Use compatible numbers to estimate 5 × 1,021
leonid [27]

Answer:

the correct answer is D

Step-by-step explanation:

5 x 1,021 = 5,105

6 0
3 years ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

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          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
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