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Lena [83]
3 years ago
5

Which statement describes the behavior of the function f (x) = StartFraction 3 x Over 4 minus x EndFraction? The graph approache

s –3 as x approaches infinity. The graph approaches 0 as x approaches infinity. The graph approaches 3 as x approaches infinity. The graph approaches 4 as x approaches infinity.
Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0

Answer:

A: the graph approaches-3 as x approaches infinity

Step-by-step explanation:

Lisa [10]3 years ago
3 0

Answer:

A: the graph approaches-3 as x approaches infinity

Step-by-step explanation:

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1/9 of the cube

Step-by-step explanation:

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Z= -19i +14 what is the real part of z?
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Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
Please help me it’s due today please help me please please people help me please please
SCORPION-xisa [38]

Answer:

a) 0≠ -10

b) x= -3

c)y= 0

Step-by-step explanation:

a) 3-4x=-7-4x

3-4x=-7-4x\\Adding \ 4x \ on \ both \ sides\\3-4x+4x=-7-4x+4x\\3-0=-7\\Adding \ -3\\3-0-3=-7-3\\0\neq -10

So, this equation has no solution as both sides are not equal.

b) 15-2x=-7x

Solving:

15-2x=-7x\\Adding \ 2x \ on \ both \ sides\\15-2x+2x=-7x+2x\\15=-5x\\Divide \ both \ sides \ by -5\\x=-3

So, this equation has one solution

c) 7(y-3)=6y-21

Solving:

7(y-3)=6y-21\\7y-21=6y-21\\Adding \ -6y \ on \ both \ sides\\7y-21-6y=6y-21-6y\\y=-21+21\\y=0

So, this equation has one solution.

1. Write equation with no solution. 3-4x=-7-4x (check solution of a)

2. Write equation with one solution. 7(y-3)=6y-21 (check solution of c)

3. Write equation with infinite solution. 2x + 3 = x + x + 3

solving:

2x+3=2x+3

2x-2x+3=3

3=3

When both sides are equal, the equation has infinite solutions.

6 0
3 years ago
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