A primary school has a running track.
1 answer:
Answer:
Distance around the track = 194.3 metres.
Step-by-step explanation:
Given: The two straight sides are of the track are 50 metres each
Diameter of each bend = 30 metres
Thus;
radius of the bends =
=
= 15 metres
So that,
length of the semicircular bend = x 2
r
= r =
x 15
= 47.143
length of each semicircular bend is 47.14 metres.
Distance around the track = addition of the length of each straight sides + addition of the length of the bends
= 50 + 50 + 47.14 + 47.14
= 194.28
Therefore,
Distance around the track = 194.3 metres.
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Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
