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balu736 [363]
3 years ago
14

A compound is known to contain 15% sulfur.

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

Answer:

30g

Explanation:

According to this question, a sulfur-containing compound is said to contain 15 percent by mass of sulfur. This means that 15% of the total mass of the compound is the mass of sulfur in the compound.

The question further states that there is a total of 200g of the compound containing sulfur, this means that the mass of sulfur can be calculated this:

Mass of sulfur = 15% of 200g

15/100 × 200g

15 × 2

30g

Hence, there are 30g of sulfur in 200g of the sulfur containing compound.

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A hydrogen atom in an excited state emits a photon of frequency ν = 3.084 x 1015 s-1. If the electron returns to the ground stat
VLD [36.1K]

<u>Answer:</u> The photon was emitted from the 4th energy level

<u>Explanation:</u>

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light  

c = speed of light = 3\times 10^8m/s

\nu = frequency of light = 3.084\times 10^{15}s^{-1}

Putting the values in above equation, we get:

\lambda=\frac{3\times 10^8m/s}{3.084\times 10^{15}s^{-1}}=9.73\times 10^{-8}m

To calculate the initial level, we use the equation given by Rydberg's equation, which is:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )

where,

\lambda = Wavelength of radiation  9.73\times 10^{-8}m

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Final energy level =  1  

n_i= Initial energy level =  ?

Putting the values, in above equation, we get

\frac{1}{9.73\times 10^{-8}m}=1.097\times 10^7m^{-1}\left(\frac{1}{1^2}-\frac{1}{n_i^2} \right )

n_i=4

Hence, the photon was emitted from the 4th energy level

4 0
3 years ago
State three uses of acid base titrations​
Bond [772]

Answer:

I can think of these three.  

Explanation:

1. To determine the concentration of an acid or base.

If you exactly neutralize an acid or base by titrating it with a standard solution, you can calculate its concentration  

2. To determine the pKₐ or pKb of an acid or base

If you draw a titration curve, the pK of the sample is the pH when you have added half the volume of titrant needed to reach the end point.

3. To follow the rate of a reaction

If a reaction produces an acid or base, you can titrate the product as it is formed. The volume of titrant will be a measure of the rate of the reaction.

5 0
3 years ago
2.50 g of an unknown base is dissolved in 289 mL of water and has a concentration of 0.216 M. What is the identification of the
AnnyKZ [126]

Answer:

The answer to your question is: A. NaOH

Explanation:

Data

mass = 2.5g of unknown base

volume = 289 ml = 0.289 l

concentration = 0.216 M

What is the base= ?

Formula

 Molarity (M) = # moles / Volumen (V)

 # moles = M x V

Process

# moles = 0.216 x 0.289 = <u>0.062     in the solution</u>

MW NaOH = 23 + 16 + 1 = 40 g

MW LiOH = 7 + 16 + 1 = 24 g

MW KOH = 39 + 16 + 1 = 56 g

Rule of three

                        40 g of NaOH ------------------- 1 mol

                        2.5 g               --------------------  x

                 x = 2.5 x 1 /40 = <u>0.062 moles</u>  is the same amount of moles in the

                                                                    solution is the answer

                         24 g of LiOH ----------------- 1 mol

                         2.5 g         ---------------------   x

                x = 2.5 x 1 / 24 = 0.104 moles

                      56 g of KOH ------------------ 1 mol

                      2.5 g             --------------------  x

                x = 2.5 x 1 / 56 = 0.045

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The 5 levels consist of individual, population, community, biome, and biosphere.
Please vote my answer brainliest!
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