Answer: The isotope is represented as 
Explanation:
General representation of an element is given as:
where,
Z represents Atomic number
A represents Mass number
X represents the symbol of an element
Atomic number is defined as the number of protons or number of electrons that are present in an atom.
Atomic number = Number of electrons = Number of protons = 7 (for nitrogen)
Mass number is defined as the sum of number of protons and neutrons that are present in an atom.
Mass number = Number of protons + Number of neutrons = 7+8 = 15
Thus the isotope is represented as
Answer:
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1
Explanation:
because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
Answer: The ratio of conjugate base to weak acid in the buffer system is 758 : 1
Explanation:
The dissociation constant for acid = 
pH = 6.34
First we have to calculate the value of 
.
The expression used for the calculation of is,
Now put the value of 
in this expression, we get:
Now we have to calculate the ratio of conjugate base to weak acid in the buffer system
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[\text {conjugate base}]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5B%5Ctext%20%7Bconjugate%20base%7D%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:
![6.34=3.46+\log \frac{[\text {conjugate base}]}{[Acid]}](https://tex.z-dn.net/?f=6.34%3D3.46%2B%5Clog%20%5Cfrac%7B%5B%5Ctext%20%7Bconjugate%20base%7D%5D%7D%7B%5BAcid%5D%7D)
![\frac{[\text {conjugate base}]}{[Acid]}=758](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5Ctext%20%7Bconjugate%20base%7D%5D%7D%7B%5BAcid%5D%7D%3D758)
Therefore, the ratio of conjugate base to weak acid in the buffer system is 758: 1
Answer:
The total energy but the photons will give is 6.615 x 10^-14
Explanation:
Formula that can be used in this question is E= hf or E= hc/ λ
This is the formula that can be used to calculate the energy that the photon is carrying where it is given as the Planck's Constant .
Now putting the values given in the equation that can calculate energy we get Planck's Constant is equal to 6.62 x 10^-34
E=(6.62 x 10^-34 x 2.998 x 10^8) / ( 3 x 10^-12 )
E=6.615 x 10^-14
