Decrease the temperature of the oxygen because if coal goes air born it can explode and wipe out power plants like they were not there
ωєℓℓ тнє ρнσѕρнσяι¢ α¢ι∂ мσℓє¢υℓєѕ αттα¢н тσ тнє мσℓє¢υℓєѕ σf тнє мιℓк, αи∂ тнαт ιи¢яєαѕєѕ тнє ∂єиѕιту αи∂ тнєи ѕєρєяαтєѕ тнєм fяσм тнє яєѕт σf тнє ℓιqυι∂ ιи ιт. тнє яємαιи∂єя σf тнє ℓιqυι∂ѕ,иσω нανιиg ℓєѕѕ ∂єиѕιту тнαи тнє ρнσѕρнσяι¢ α¢ι∂ѕ & тнє мιℓк мσℓє¢υℓєѕ, ѕσ ιт ιт иσω fℓσαтѕ σи тσρ.
нσρє ι ¢συℓ∂ нєℓρ уσυ.
I think the answer is that they both don’t have a full outer shell
i hope this helps
Answer:
V₂ =279.4 cm³
Explanation:
Given data:
Initial volume = 260 cm³
Initial temperature = 22.0°C
Final temperature = 44.0°C
Final volume = ?
Solution;
22.0°C (22+ 273 = 295k)
44.0°C(44+273 = 317k)
Formula:
According to Charles's law
V₁/T₁ = V₂/T₂
Now we will put the values in formula:
V₂ = V₁×T₂ / T₁
V₂ = 260 cm³ × 317k / 295k
V₂ = 82420 cm³. k / 295k
V₂ =279.4 cm³
Answer:
The reaction can produce 287 grams of iron(II) carbonate
Explanation:
To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-
<em>Moles FeCl2:</em>
1.24L * (2.00mol / L) = 2.48 moles FeCl2
As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles
<em>Mass FeCO3:</em>
2.48mol * (115.854g / mol) =
<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
