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MrRa [10]
3 years ago
11

If 112 sections are 34 mile long, how long is each section?

Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

About 3.29 miles long for each section

Step-by-step explanation:

Find unit rate so 112/34 and you’d get 3.29 rounded.

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70 POINTS! PLEASE HELP! Explain the difference between the following equation formats: Slope-Intercept, Point-Slope and Standard
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Answer and Step-by-step explanation:

1.  slope intercept

2.  point-slope form

3.  standard

Explanation:

1.   A <u>slope intercept form</u> equation is when it's set up as y = m x + b

m = slope  

b = y-intercept

2.   <u>A point-slope form</u> is when a line passes through a point

and the equation is set up as  y −b = m ( x−a)

m = slope

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3. <u>standard lope form</u> is when the equation is set up as

Ax + By = C

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3 years ago
There are 23 classes in the fourth grade. Each grade has 21 students. Write a number sentence that will provide a reasonable est
lapo4ka [179]
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3 years ago
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

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Answer:

1.40x I think :)

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