Answer:
(x,y)=(0,7.333)
Step-by-step explanation:
We are required to:
Maximize p = x + 2y subject to
- x + 3y ≤ 22
- 2x + y ≤ 14
- x ≥ 0, y ≥ 0.
The graph of the lines are plotted and attached below.
From the graph, the vertices of the feasible region are:
At (0,7.333), p=0+2(7.333)=14.666
At (4,6), p=4+2(6)=4+12=16
At (0,0), p=0
At (7,0), p=7+2(0)=7
Since 14.666 is the highest, the maximum point of the feasible region is (0,7.333).
At x=0 and y=7.333, the function p is maximized.
Answer:
1/2
Step-by-step explanation:
The formula for the slope given two points is
m = (y2-y1)/(x2-x1)
= (1--2)/(8-2)
= (1+2)/(8-2)
=3/6
1/2
I will assume that the two equations are
1) y = -x^2 +2x + 4 and 2) x +y = 4
subtract 2 from 1 and you get
y -x - y = -x^2 + 2x + 4 - 4
-x = -x^2 +2x
x^2 -x -2x = 0
x^2 - 3x = 0
x(x-3)=0
x=0 and x - 3 =0
x=0 and x = 3
Then y = 4 - x
y = 4 - 0 and y = 4 -3
y = 4 and y =1
Solutions:
Points (0,4) and (3,1)