Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is
KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
D leafs because it contains chlorophyll
Answer:
2.1 x 10¹²ng
Explanation:
Mass of the calcium carbonate given is:
2.1kg
We need to take this mass to nanogram, ng.
Since :
1000g = 1kg
10⁹g = 1ng
So;
1kg = 1000 x 10⁹ = 10¹²ng
So;
2.1kg will give;
Since
1kg gives 10¹²ng
2.1kg will give 2.1 x 10¹²ng
Answer:
Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)
Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)
Mn | Mn²⁺ || Zn²⁺ | Zn
Explanation:
To identify the half reaction we need to see the oxidation states.
Mn(s) → Ground state → Oxidation state = 0
Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.
This is the oxidation reaction. It has released two electrons:
Mn → Mn²⁺ + 2e⁻
Zn(NO₃)₂ → Zn²⁺
Zn → Ground state → The oxidation state was decreased.
This is the reduction reaction. It has gained two electrons:
Zn²⁺ + 2e⁻ → Zn
Cathode: Mn → Mn²⁺ + 2e⁻
Anode: Zn²⁺ + 2e⁻ → Zn
Mn | Mn²⁺ || Zn²⁺ | Zn
<h2>
Answer:</h2>
We will use dimensional analysis to solve this.
We will need the molar mass of barium, which is 137.33 g/mol.
50g × 
= .36 mol Ba
There are <em>.36 moles of barium</em> in 50g of barium
